有如下四個(gè)結(jié)論:
①(a+b)5=a5+5a4b+10a3b2+10a2b3+5ab4+b5;
②當(dāng)a=-2,b=1時(shí),代數(shù)式a3+3a2b+3ab2+b3的值是-1;
③當(dāng)代數(shù)式a4+4a3b+6a2b2+4ab3+b4的值是0時(shí),一定是a=-1,b=1;
④(a+b)n的展開(kāi)式中的各項(xiàng)系數(shù)之和為2n.
上述結(jié)論中,正確的有(寫出序號(hào)即可).
已知 , , 求的值;
例如:如圖①是一個(gè)長(zhǎng)為 , 寬為的長(zhǎng)方形,沿圖中虛線用剪刀均分成四個(gè)小長(zhǎng)方形,然后按圖②的形狀拼成一個(gè)正方形.請(qǐng)解答下列問(wèn)題:
方法1:;
方法2:;
由此可以得出、、之間的等量關(guān)系是;
解:因?yàn)?img class="mathml" src="http://math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmi%3Ea%3C%2Fmi%3E%3Cmo%3E%2B%3C%2Fmo%3E%3Cmi%3Eb%3C%2Fmi%3E%3Cmo%3E%3D%3C%2Fmo%3E%3Cmn%3E3%3C%2Fmn%3E%3C%2Fmath%3E" style="max-width:100%;vertical-align: middle;"> , 所以 , 即 .
又因?yàn)?img class="mathml" src="http://math.21cnjy.com/MathMLToImage?mml=%3Cmath+xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F1998%2FMath%2FMathML%22%3E%3Cmi%3Ea%3C%2Fmi%3E%3Cmi%3Eb%3C%2Fmi%3E%3Cmo%3E%3D%3C%2Fmo%3E%3Cmn%3E1%3C%2Fmn%3E%3C%2Fmath%3E" style="max-width:100%;vertical-align: middle;"> , 所以 .
根據(jù)上面的解題思路與方法,解決下列問(wèn)題: